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5 mole of an ideal gas with gamma = 7/5 initially at STP are compressed adiabatically so that its temperature becomes 400^@C. The increase in the internal energy of gas in kJ is |
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Answer» 21.55 `dU=(nR DT)/(gamma-1)` `=(5xx8.31xx(400-0))/((7//5)-1)`= 41550 J = 41.55 kJ |
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