1.

5 mole of SO_(2)and 5 moles of O_(2) are allowed to react. At equlibrium, it was found that 60% of SO_(2) is used up. If the partial pressure of the equlibrium mixture is one atmosphere, the partial pressure of O_(2) is

Answer»

`0.52` ATM
`0.21` atm
`0.41` atm
`0.82` atm

Solution :Initially `underset(5)(2SO_(2(G)))+underset(5)(O_(2(g)))hArrunderset(0)(2SO_(3(g)))`
Degree of dissociation `=0.60`
`therefore` no of MOLES of `SO_(2)` at equlibrium =2
no of moles of `O_(2)` atequlibrium =3.5
no of moles of `SO_(3)` PRODUCED at equlibrium=3
`therefore pO_(2)=(3.5xx1)/(8.5)=0.41atm.`


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