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    				| 1. | 5 MOLES OF AN IDEAL GAS ARE TAKEN IN A CARNOT ENGINE WORKING BETWEEN 100 . C-30 . C. THE USEFUL WORKDONE IN 1 CYCLE IS 420J. CALCULATE THE RATIO OF THE VOLUME OF THE GAS AT THE END AND BEGINNING OF THE ISOTHERMAL EXPANSION. (TAKE R = 8.4 J/mol K) | 
| Answer» The work done during isothermal expansion is given asW = 2.303nRT.ln(Vf/ Vi)so,ln(Vf/ Vi) = W / 2.303nRTor ratio will be given as(Vf/ Vi) = exp[W / 2.303nRT]here,Vf= final volumeVi= initial volumen = 5R = 8.314 J/KmolT = 100C = 373Kand W = 420Jthus,(Vf/ Vi) = exp[420 / (2.303 x 5 x 8.314 x 373)]or(Vf/ Vi) = exp[(420 / 7141.883)]thus(Vf/ Vi) = 1.059 | |