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5 persons A, B, C, D and E are in a queue of a shop. The probability that A and E always occur together, isA. `(1)/(4)`B. `(2)/(3)`C. `(2)/(5)`D. `(3)/(5)`

Answer» Correct Answer - C
5 persons A, B, C, D and E can stand in a queue in 5! Ways.
Persons A and E can occur together in 2! Ways.
Considering A and E as one person, there are 4 persons who can be queued in 4! Ways.
So, A and E can occur together in `4!xx2!` ways.
So, required probability `=(4!xx2!)/(5!)=(2)/(5)`


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