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5 Principal Rs.6,000 for 12 years at 10% per annum. Find the following:ii) compound interest isA) Rs. 903B) Rs. 909C) Rs. 900D) Rs. 930 |
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Answer» Answer:375 Step-by-step explanation: LET the sum be Rs.x Amount after 3 years on Rs.x at 20% per annum when interest is compounded annually = P ( 1 + R 100 ) T = x ( 1 + 20 100 ) 3 = x ( 120 100 ) 3 = x ( 6 5 ) 3 Compound Interest = x ( 6 5 ) 3 − x = x [ ( 6 5 ) 3 − 1 ] = x [ 216 − 1 ] = 91 x 125 Simple Interest = PRT 100 = x × 20 × 3 100 = 3 x 5 =P(1+R100)T=x(1+20100)3=x(120100)3=x(65)3Compound Interest = x(65)3−x=x[(65)3−1]=x[216125−1]=91x125Simple Interest = PRT100=x×20×3100=3x5 Given that DIFFERENCE between compound interest and simple interest is Rs.48 91 x 125 − 3 x 5 = 48 91 x − 75 x 125 = 48 16 x 125 = 48 x = 48 × 125 16 = 3 × 125 = Rs. 375 91x125−3x5=4891x−75x125=4816x125=48x=48×12516=3×125=Rs. 375 i.e, the sum is Rs.375 -------------------------------------------------------------------------------------- Solution 2 --------------------------------------------------------------------------------------- The difference between compound interest and simple interest on Rs. P for 3 years at R% per annum = P ( R 100 ) 2 ( R 100 + 3 ) =P(R100)2(R100+3) [Read more ...] P ( R 100 ) 2 ( R 100 + 3 ) = 48 P ( 20 100 ) 2 ( 20 100 + 3 ) = 48 P ( 1 5 ) 2 ( 1 5 + 3 ) = 48 P ( 1 25 ) ( 16 5 ) = 48 P = 48 × 25 × 5 16 = 3 × 25 × 5 = 375 |
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