1.

5. Represent V10.5 geometrically on the number line.​

Answer» <html><body><p><strong>Answer:</strong></p><p><strong>We </strong><strong>can </strong><strong>do </strong><strong>it </strong><strong>by </strong><strong>using </strong><strong>phythagoras</strong><strong> </strong><strong>theorem</strong><strong> </strong></p><p><strong>Step-by-step explanation:</strong></p><p><strong>We </strong><strong><a href="https://interviewquestions.tuteehub.com/tag/acn-361659" style="font-weight:bold;" target="_blank" title="Click to know more about ACN">ACN</a> </strong><strong>√</strong><strong> </strong><strong>1</strong><strong>0</strong><strong> </strong><strong>as </strong><strong>follows</strong><strong> </strong></p><p><strong>√</strong><strong>1</strong><strong>0</strong><strong> </strong><strong>=</strong><strong> </strong><strong>√</strong><strong>9</strong><strong>+</strong><strong>1</strong><strong> </strong></p><p><strong>&gt;</strong><strong> </strong><strong>√</strong><strong>1</strong><strong>0</strong><strong> </strong><strong>=</strong><strong> </strong><strong>√</strong><strong>3</strong><strong>s</strong><strong>q</strong><strong>a</strong><strong>u</strong><strong>r</strong><strong>e</strong><strong> </strong><strong>+</strong><strong> </strong><strong>1</strong><strong> </strong><strong>square</strong></p><h2><strong>the </strong><strong>constraction</strong><strong> </strong><strong>steps </strong><strong>are </strong><strong>as </strong><strong>follows</strong><strong> </strong></h2><p><strong>.</strong><strong> </strong><strong>Take </strong><strong>the </strong><strong>line </strong><strong>seg</strong><strong>m</strong><strong>ent </strong><strong>AO</strong><strong> </strong><strong>=</strong><strong> </strong><strong>3</strong><strong> </strong><strong>unit </strong><strong>on </strong><strong>the </strong><strong>x </strong><strong>-</strong><strong> </strong><strong><a href="https://interviewquestions.tuteehub.com/tag/axis-889931" style="font-weight:bold;" target="_blank" title="Click to know more about AXIS">AXIS</a> </strong><strong>(</strong><strong> </strong><strong>consider </strong><strong>1</strong><strong> </strong><strong>unit </strong><strong>=</strong><strong> </strong><strong>1</strong><strong>0</strong><strong> </strong><strong>c</strong><strong>m</strong><strong> </strong><strong>)</strong><strong> </strong></p><p><strong>.</strong><strong> </strong><strong>Draw </strong><strong>a </strong><strong>perpendicular</strong><strong> </strong><strong>on </strong><strong>O </strong><strong>and </strong><strong>draw </strong><strong>a </strong><strong>line </strong><strong>OC </strong><strong>=</strong><strong> </strong><strong>1</strong><strong> </strong><strong>unit </strong></p><p><strong>.</strong><strong> </strong><strong>Now </strong><strong><a href="https://interviewquestions.tuteehub.com/tag/join-1061908" style="font-weight:bold;" target="_blank" title="Click to know more about JOIN">JOIN</a> </strong><strong>AC </strong><strong>in </strong><strong>√</strong><strong> </strong><strong>1</strong><strong>0</strong><strong> </strong></p><p><strong>.</strong><strong> </strong><strong>Take </strong><strong>A </strong><strong>as </strong><strong>centre </strong><strong>amd </strong><strong>AC </strong><strong>as </strong><strong>radius</strong><strong> </strong><strong>,</strong><strong> </strong><strong>dr</strong><strong>a</strong><strong>w </strong><strong>a </strong><strong>arc </strong><strong>which </strong><strong>cuts </strong><strong>x </strong><strong>-</strong><strong> </strong><strong>axi</strong><strong>s</strong><strong> </strong><strong>at </strong><strong>point </strong><strong>E </strong></p><p><strong>.</strong><strong> </strong><strong>The </strong><strong>line </strong><strong>segment</strong><strong> </strong><strong>AC </strong><strong>in </strong><strong>he </strong><strong>below </strong><strong>daigram</strong><strong> </strong><strong>explain</strong><strong> </strong><strong>the </strong><strong>unit </strong><strong>√</strong><strong> </strong><strong>1</strong><strong>0</strong><strong> </strong></p><p></p><p><strong><em>hope</em></strong><strong><em> it</em></strong><strong><em> it</em></strong><strong><em> will</em></strong><strong><em> help</em></strong><strong><em> you</em></strong></p><p><strong><em>please</em></strong><strong><em> mark</em></strong><strong><em> me</em></strong><strong><em> as</em></strong><strong><em> a</em></strong><strong><em> brain</em></strong><strong><em> list</em></strong><strong><em> friends</em></strong></p></body></html>


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