5.Sum of two numbers is 95. If one exceeds the other by 3, find the nu

1.	5.Sum of two numbers is 95. If one exceeds the other by 3, find the numbers.
Answer» Answer: Let the ONE number be x and the other number be y. It is given that the sum of the numbers is 95, therefore, we have: x+y=95....(1) It is also given that one number exceeds the other by 3 which MEANS: x=y+3 ⇒x−y=3....(2) Now, we add equations 1 and 2 as follows: x+y+x−y=95+3 ⇒(x+x)+(y−y)=98 ⇒2x=98 ⇒x= 2 98 ⇒x=49 Now, substitute the value of x in EQUATION 2 to find the value of y as shown below: x−y=3 ⇒49−y=3 ⇒y=49−3 ⇒y=46 Therefore, the two numbers are x=49 and y=46 and the product of the numbers is: x×y=49×46=2254. Hence, the product of the numbers is 2254

5.Sum of two numbers is 95. If one exceeds the other by 3, find the numbers.

Answer»

Answer:

Let the ONE number be x and the other number be y.

It is given that the sum of the numbers is 95, therefore, we have:

x+y=95....(1)

It is also given that one number exceeds the other by 3 which MEANS:

x=y+3

⇒x−y=3....(2)

Now, we add equations 1 and 2 as follows:

x+y+x−y=95+3

⇒(x+x)+(y−y)=98

⇒2x=98

⇒x=

⇒x=49

Now, substitute the value of x in EQUATION 2 to find the value of y as shown below:

x−y=3

⇒49−y=3

⇒y=49−3

⇒y=46

Therefore, the two numbers are x=49 and y=46 and the product of the numbers is:

x×y=49×46=2254.

Hence, the product of the numbers is 2254