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5.The locus of the point x = a cos theta, y= b sin theta |
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Answer» Step-by-step EXPLANATION:It is GIVEN that x=a(cosθ+sinθ) y=b(cosθ−sinθ) Now bx=ab(cosθ+sinθ) ...(i) ay=ab(cosθ−sinθ) ...(ii) HENCE, b 2 x 2 +a 2 y 2 =a 2 b 2 (cos 2 θ+sin 2 θ+2cosθsinθ+cos 2 θ+sin 2 θ−2cosθsinθ) =a 2 b 2 (2(cos 2 θ+sin 2 θ)) =2a 2 b 2 Hence, b 2 x 2 +a 2 y 2 =2a 2 b 2 Dividing the entire equation by a 2 b 2 GIVES us a 2 x 2 + b 2 y 2 =2 markme as brainlist plz |
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