5.The sides of a rectangle are 3 a2 +6b and 4 a2 + b. Fiņd its perime

1.	5.The sides of a rectangle are 3 a2 +6b and 4 a2 + b. Fiņd its perimeter?.6. What should be added to a2 + 2ab + b2 to obtain 2 a2 + 4ab?
Answer» Step-by-step explanation: 5)LET, LENGTH of the rectangle=3a²+6b breadth of the rectangle=4a²+4ab perimeter of the rectangle=2(length+breadth) =2(3a²+6b+4a²+b) =2(7a²+7b) =14a²+14b 6)Let, the number to be added be x so,x+a²+2ab+b²=2a²+4ab or,x=(2a²+4ab)-(a²+2ab+b²) or,x=2a²+4ab-a²-2ab-b² or,x=a²+2ab-b²

5.The sides of a rectangle are 3 a2 +6b and 4 a2 + b. Fiņd its perimeter?.6. What should be added to a2 + 2ab + b2 to obtain 2 a2 + 4ab?

Answer»

Step-by-step explanation:

5)LET, LENGTH of the rectangle=3a²+6b

breadth of the rectangle=4a²+4ab

perimeter of the rectangle=2(length+breadth)

=2(3a²+6b+4a²+b)

=2(7a²+7b)

=14a²+14b

6)Let, the number to be added be x

so,x+a²+2ab+b²=2a²+4ab

or,x=(2a²+4ab)-(a²+2ab+b²)

or,x=2a²+4ab-a²-2ab-b²

or,x=a²+2ab-b²