50.0 g sample of brass is dissolved in 1 L dil `H_2SO_4.20mL` of this solution is mixed with KI, and the liberated `I_2` required 20 " mL of " 0.5 M hypo solution for titration calculate the amount of Cu in the alloy.

50.0 g sample of brass is dissolved in 1 L dil `H_2SO_4.20mL` of this

1.	50.0 g sample of brass is dissolved in 1 L dil `H_2SO_4.20mL` of this solution is mixed with KI, and the liberated `I_2` required 20 " mL of " 0.5 M hypo solution for titration calculate the amount of Cu in the alloy.
Answer» `Cu-=CuSO_4-=KI-=I_2-=Na_2S_2O_3` `mEq-=mEq-=mEq-=mEq` `?-=--=--=20xx0.5xx1(n=1)` `=(10 m" Eq of "Na_2S_2O_3)/(20 mL "of solution")` `-=(10xx1000)/(20)mEqL^(-1)=500mEqL^(-1)` of solution m" Eq of "Cu `=500xx10^(-3)xx(63.5)/(1)` (n-factor `=1`) `=(635xx5)/(100)=31.75g` `%` `Cu=(31.75)/(50)xx100=63.5%`

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50.0 g sample of brass is dissolved in 1 L dil `H_2SO_4.20mL` of this solution is mixed with KI, and the liberated `I_2` required 20 " mL of " 0.5 M hypo solution for titration calculate the amount of Cu in the alloy.

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