1.

50 mL of 0.1 M CuSO_(4) solution is electrolysed using Pt electrodes with a current of 0.965 ampere for a period of 1 minute. Assuming that volume of solution does not change during electrolysis, calculate [Cu^(2+)], [H^(+)] and [SO_(4)^(2-)] after electrolusis. What will be the concentration of each species if current is passed using Cu electrodes ?

Answer»


ANSWER :`[CU^(2+)] = 0.094M, [H^(+)] = 0.012 M, [SO_(4)^(2-)] = 0.1 M ;`


Discussion

No Comment Found