1.

50 ml of 0.1 M HCl and 50 ml of 0.2 M NaOH are mixed. The pH of the resulting solution is :

Answer»

`1.30`
`4.2`
`12.70`
`11.70`

Solution :`[H^(+)]` in 50 ml of 0.1 M HCl
`=(0.1xx50)/(1000)=0.005 M`
`[OH^(-)]`in 50 ml of 0.2 M NaOH
`=(0.2xx50)/(1000)=0.010 M`
EXCESS of `OH^(-)` ions present after neutralisation
`=0.010-0.005=0.005`
Concentration of `OH^(-)`
`=(0.005)/(100)xx1000=0.05 M`
`pOH=-log[OH^(-)]=-log0.05=1.30`


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