1.

50 ml of 1 M acetic acid is skaken with 0.5 g wood charcoal. The final conc. of the solution after adsorption is 0.5 M. What is the amount of acetic acid adsorbed per gram of carbon?

Answer»


SOLUTION :`M = (wt)/(GMT) cdot (1000)/V , 1 = (wt)/(60) cdot 1000/50 " wt= 3 after " 0.5 = (wt)/(60) cdot (1000)/(50) wt = 15`
adsorbed = `(3 - 1.5) = 1.5 = 0.5 gr to 1.5 {:(1 to ?),(0,3):}`


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