1.

50 ml of 1 M oxalic acid is shaken with 0.5 g wood charcoal. The final concentration of the solution after adsorption is 0.5 M. What is the amount of oxalic acid adsorbed per gram of carbon?

Answer»

3.15 G
3.45 g
6.30 g
NONE of these.

Solution :Amountof oxalicacid intitallypresent`= (1 xx 50)/(1000) xx 63 = 3.15g `
Amountof oxalicacidafter adsorption.
` = (50)/(1000) xx 63 xx 0.5 = 1.575 g`
Amountadsorbed` = 3.15 - 1.575 = 1.575 g`
Amountadsrobedper GRAM of charocoal`= 1.575 xx 2= 3.15 g`


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