1.

50 mL of 1 M oxalic acid (molecule mass = 126) is shaken with 0.5 g of oxalic acid adsorbed per gram gram of chrocoal.

Answer»

Solution :CALCULATION of initial amount of oxalic acid in 50 mL solution. 1 M oxalic acid solution means 1 mole of oxalic acid (126 g) present in 1000 mL solution.
`THEREFORE` 50 mL of 1 M solution will CONTAIN oxalic acid `=(126)/(1000)xx50=6.6g`
Calculation of amount of oxalic acid in 50 mL solution after adsorption. Conentration of solution after adsorption `=0.5M.` Thus, 1000 mL of the solution contain oxalic acid `=(63)/(100)xx50=3.15g`
Calculation of amount adsorbed per gram
Amount of oxalic acid adsorbed by `0.5` g charcoal `=6.30-3.15g =3.15g`
`therefore` Amount of oxalic acid adsorbed per gram of charcoal `=6.30g`


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