50 ml of a gaseous hydrocarbon (having 85.7% carbon) at STP on combust – InterviewSolution

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1.	50 ml of a gaseous hydrocarbon (having 85.7% carbon) at STP on combustion with oxygen gave 0.370 g of CO_2, 0.142 g H_2 O and an undetermined quantity of methane. The molecule formula of hydrocarbon will be:
Answer» `C_4 H_8` `C_2 H_2` `C_5 H_8` `C_2 H_4` ANSWER :A

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