1.

50 ml water is added to a 50 ml solution of Ba(OH)_(2) of strength 0.01 M. The pH value of the resulting solution will be

Answer»

8
10
12
6

Solution :`0.01 M Ba(OH)_(2) = 0.02 N (Ba(OH)_(2)`
`N_(1)V_(1) = N_(2)V_(2)`
`[0.02 N] xx [ 50 ml] = N_(2)xx 100 ml`
`N_(2) = (0.02 xx 50)/(100) = 10^(-2) N, [OH^(-)] = 10^(-2) N`
`pOH = 2` or PH = 12.


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