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50 turns of a wire of diameter 1mm is wound on a cylinder of radius 5 cm. If the specific resistance of the materical of the wire is `4.5xx10^-6Omegam`, then its resistance isA. `9kOmega`B. `900Omega`C. `250 Omega`D. `90Omega` |
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Answer» Correct Answer - D `n=50,r=0.5mm,a=5cm,rho=4.5xx10^-6Omega m, R=?` `R=(rho^l)/(A)=(rho^l)/(pir^2)=(rho.2pia.n)/(pi r^2)` `therefore R=(rho2an)/(r^2)=(4.5xx10^-6xx2xx5xx10^-2xx50)/(0.25xx10^-6)` `therefore R=9 0 Omega` |
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