1.

500cc of a hydrocarbon gas burnt in excess of oxygen yields 2500cc of CO_(2) and 3 litres of H_(2)O vapour, all the vapours being meausred at the same temperature and pressure. What si the formula of the hydrocarbon gas?

Answer»

Solution :`{:(,"Hydrocarbon",overset("combustion")rarr,CO_(2),+,H_(2)O),(,0.5 lit,,2.5lit,,3lit),(,0.5"moles",,2.5 "moles",,3"moles"),(THEREFORE, 1"moles",,5 "moles",,6 "moles"):}`
Moles of C in `CO_(2)=1 xx` moles of `CO_(2)`
`=1 xx5 =5`
Moles of H in `H_(2)O=2xx` moles of `H_(2)O`
`=2 xx 6= 12`
SINCE 1 mole of the compound contains 5 moles of C and 12 moles of H, the molecular formula of the hydrocarbon is `C_(5)H_(12)`


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