1.

500ml of NH_(3) contains 6.00 xx 10^(23) molecules at S.T.P. How many molecules are present in 100 ml of CO_(2) at S.T.P.

Answer»

`6 xx 10^(23)`
`1.5 xx 10^(23)`
`1.2 xx 10^(23)`
None of these

Solution :`(PV_(1))/(n_(2)RT)=(PV_(2))/(n_(2)RT)` or , `(V_(1))/(n_(1))=(V_(2))/(n_(2))`
or , `(500)/(1)=(100)/(n_(2))` or , `n_(2)=(1)/(5)`
`[6.0 xx 10^(23)` molecules of `NH_(3)=1` mole ]
1 mole of `CO_(2)` contains `6.0 xx 10^(23)` molecules
`:. (1)/(5)` mole of `CO_(2)` contains `1.2 xx 10^(23)` molecules


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