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500ml of `NH_(3)` contains `6.00 xx 10^(23)` molecules at S.T.P. How many molecules are present in 100 ml of `CO_(2)` at S.T.P.A. `6 xx 10^(23)`B. `1.5 xx 10^(23)`C. `1.2 xx 10^(23)`D. None of these |
Answer» Correct Answer - C `(PV_(1))/(n_(2)RT)=(PV_(2))/(n_(2)RT)` or , `(V_(1))/(n_(1))=(V_(2))/(n_(2))` or , `(500)/(1)=(100)/(n_(2))` or , `n_(2)=(1)/(5)` `[6.0 xx 10^(23)` molecules of `NH_(3)=1` mole ] 1 mole of `CO_(2)` contains `6.0 xx 10^(23)` molecules `:. (1)/(5)` mole of `CO_(2)` contains `1.2 xx 10^(23)` molecules |
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