1.

50mL of each gas A and of gas B takes 150 and 200 seconds respectively for effusing through a pin hole under the similar conditions. If molecular mass of gas B is 36, the molecular mass of gas A will be :

Answer»

64
96
128.4
20.2

Solution :`(r_(1))/( r_(2)) = ( v_(1) //t_(1))/( v_(2) //t_(2)) = SQRT((M_(B))/( M_(A)))`
`(t_(2))/( t_(1)) = sqrt((M_(B))/( M_(A))) ( :. v_(1) = v_(2))`
`( 200)/( 150) = sqrt(( 36)/( M_(A)))`
or `( 36)/( M_(A)) = (( 200)/( 150) )^(2)= 1.78`
`:. M_(A) = ( 36)/( 1.78) = 20.23`


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