52.5millimoles ofLiAlH_(4)was treated with15.6 g (210 millimoles ) of t- butyl alcohol . A total of 157.5 millimolesof hydrogen wasevolved or for the readtion Li AIH_(4) + 3 (CH_(3))_(3) COH to 3H_(2) + Li [(CH_(3))_(3) O]_(3) ALHThe addition of an excess of anotheralcohol, methanol to the above reactionmixture caused the fourth H atom of the LiAIH_(4)to be replace according tothe equation Li [(CH_(3))_(3) O]_(3) AlH + CH_(3) OH to H_(2) + Li [(CH_(3))_(3) O] _(3) [CH_(3) O]Al How mauch H_(2)was evolved due to theaddition of CH_(3) OH?

52.5millimoles ofLiAlH_(4)was treated with15.6 g (210 millimoles ) of

1.	52.5millimoles ofLiAlH_(4)was treated with15.6 g (210 millimoles ) of t- butyl alcohol . A total of 157.5 millimolesof hydrogen wasevolved or for the readtion Li AIH_(4) + 3 (CH_(3))_(3) COH to 3H_(2) + Li [(CH_(3))_(3) O]_(3) ALHThe addition of an excess of anotheralcohol, methanol to the above reactionmixture caused the fourth H atom of the LiAIH_(4)to be replace according tothe equation Li [(CH_(3))_(3) O]_(3) AlH + CH_(3) OH to H_(2) + Li [(CH_(3))_(3) O] _(3) [CH_(3) O]Al How mauch H_(2)was evolved due to theaddition of CH_(3) OH?
Answer» Solution :According to the given EQUATIONS, 1 MOLE of Li `[(CH_(3))_(3)O]_(3)` AIHproduces1 MOLEOF `H_(2)` and 1 mole of Li `[(CH_(3))_(3)O]_(3)` AIHis produced by 1 mole of `LiAIH_(4)` `:.` 1 mole of `LiAIH_(4)` shouldproduce 1 mole of `H_(2)""(byCH_(3)OH)` or 1 MILLIMOLE of `LiAIH_(4)` should produce 1 millimole of `H_(2)(by CH_(3) OH)` 52 . 2 millimolesof `LiAIH_(4)` should produce 52.5 MILLIMOLES of`H_(2) (by CH_(3) OH)`