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540 g of ice at `0^(@)C` is mixed with 540 g of water at `80^(@)C`. The final temperature of the mixture isA. `0^(@)C`B. `40^(@)C`C. `80^(@)C`D. less than `0^(@)C` |
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Answer» Correct Answer - A Heat taken by ice to melt at `0^(@)C "is" Q_(2) = "m"L = 540xx80 = 43200"cal"` Heat given by water to cool upto `0^(@)C "is" Q_(2) = "ms"Deltatheta = 540 xx 1 x (80-0) = 43200"cal"` Hence heat given by water is just sufficient to melt the whole ice and final temperature of mixture is `0^(@)C`. |
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