56 tunning forks are arranged in a series that each fork given 4 beats/s with previous one. The frequency of last fork is 3 times that fo first. Then frequency of first fork is :

56 tunning forks are arranged in a series that each fork given 4 beats

1.	56 tunning forks are arranged in a series that each fork given 4 beats/s with previous one. The frequency of last fork is 3 times that fo first. Then frequency of first fork is :
Answer» 52 Hz 56 Hz 60 Hz 110 Hz Solution :Let the frequency of 56 forks be v, v + 4 , v + 2 `xx`4 .......... V + 55 `xx ` 4. Now v + 55 `xx` 4 = 3v. `rArr ` 2V = 220 `rArr "" ` v = 110 Hz.

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56 tunning forks are arranged in a series that each fork given 4 beats/s with previous one. The frequency of last fork is 3 times that fo first. Then frequency of first fork is :

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