1.

56g of N_(2) ( molar mass = 28) are mixed with 44g of CO_(2) ( molar mass = 44) and the pressure of the resulting gaseous mixture is 3 atm. The partial pressure of N_(2) in the mixture is :

Answer»

i. 1 atm
ii. 1.5 atm
iii. 2 atm
iv. 3 atm

Solution :Moles of `N_(2) = ( 56)/( 28) =2 `
Moles of `CO_(2) = ( 44)/( 44) = 1 `
Mole fraction of
`N_(2) = ( 2)/( 2+1) = ( 2)/(3)`
Partial PRESSURE of
`N_(2) = ( 2)/(3) xx 3 = 2 atm`


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