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InterviewSolution
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57. The equilibrium constant (K) for the reactionPC/5(g) → PC,(g) + C12(g) is 16. If the volume of thecontainer is reduced to one half its original volume, thevalue of K for the reaction at the same temperature will be(a) 32(c) 16(b) 64(d) 4 |
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Answer» PCl5dissociates as:PCl5⇌ PCl3Cl2If p is the degree of dissociation at certain temperature under atmospheric pressure, thenInitial concentration:PCl5= 1PCl3= 0Cl2= 0At Equilibrium:PCl5= 1 – pPCl3= pCl2= pTotal number of moles at equilibrium = 1 – p + p + p = 1 + pPartial pressures of PCl5, PCl3and Cl2will be:p (PCl3) = p p / 1 + pp (Cl2) = p p / 1 + pp (PCl5) = (1 – p) p / 1 + pKp= p (PCl3) X p (Cl2) / p (PCl5)Kp=[(p p / 1 + p) X (p p / 1 + p)]/[(1 – p) p / (1 + p)]= p^2p / (1 – p)^2 |
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