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5cos20° - 4sin230° + 6cosec245° = ?A. 12B. 8C. 4D. 161. C2. A3. D4. B |
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Answer» Correct Answer - Option 3 : D Given: 5cos20° – 4sin230° + 6cosec245° = ? Concept used: using the concept of trigonometric ratios Calculation: 5cos20° – 4sin230° + 6cosec245° = ? ⇒ 5 × (1)2 – 4 × (1/2)2 + 6 × (√2)2 = ? ⇒ 5 – 4 × 1/4 + 6 × 2 = ? ⇒ 5 – 1 + 12 = ? ⇒ 4 + 12 = ? ⇒ ? = 16 ∴ The value of ? is 16. |
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