1.

5g H_(2) is allowed to react with 14 g N_(2) for the following reaction. N_(2)(g)+3H_(2)(g)rarr2NH_(3)(g) What mass of H_(2) will be left unreached at the end of reaction?

Answer»


Solution :`N_(2)` OS ,o,otomg reactamt. THUS `14 g N_(2)` will give 17g `NH_(3)` and xg `H_(2)` REMAINS unreacted.
Mass before reaction =Mass after reaction
`(5+14)=(17+x)`
x=2g


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