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`5mol` of an ideal gas at `293K` is expanded isothermally from an initial pressure `0.4 kPa` to a final pressure of `0.1kPa` against a constant external pressure of `0.1kPa`. a. Calcualte `q,w, Delta,U`, and `DeltaH`. b. Calculate the corresponding value of `q,w, DeltaU`, and `DeltaH` if the above pressure is carried out reversibly. |
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Answer» a. For an isothermal expansion against a constant pressure, we have: `w =- P_(ex) (V_(2)-V_(1))` `=- P_(ex) ((nRT)/(P_(2))-(nRT)/(P_(1)))=- P_(ex) ((1)/(P_(1))-(1)/(P_(2))) =- 9135J` Since temperature is constant `DeltaU = 0, DeltaH = 0,q =- W = 9135J` b. For isothermal reversible expansion `-w = 2.303nRT "log"(P_(1))/(P_(2))` `= 2.303 xx5xx 8.324 xx 293 "log"(0.4)/(0.1)` `rArr w =- 16888J` `DeltaU = DeltaH = 0,q =- W = 16888J` |
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