1.

`(5x)^(3cos2x)`

Answer» माना `y=(5x)^(3cos2x)`
`rArr" "logy=log[(5x)^(3cos2x)]`
`" "=3 cos 2x log(5x)`
दोनों पक्षों का x सापेक्ष अवकलन करने पर
`(1)/(y)(dy)/(dx)=3[cos2x.(d)/(dx)log(5x)+log(5x).(d)/(dx)cos2x]`
`rArr" "(dy)/(dx)=3y[cos2x.(5)/(5x)+log(5x).(-2 sin 2x)]`
`rArr" "(dy)/(dx)=3.(5x)^(3cos2x)`
`" "[(cos2x)/(x)-2sin2xlog(5x)]`


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