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`(5x)^(3cos2x)` |
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Answer» माना `y=(5x)^(3cos2x)` `rArr" "logy=log[(5x)^(3cos2x)]` `" "=3 cos 2x log(5x)` दोनों पक्षों का x सापेक्ष अवकलन करने पर `(1)/(y)(dy)/(dx)=3[cos2x.(d)/(dx)log(5x)+log(5x).(d)/(dx)cos2x]` `rArr" "(dy)/(dx)=3y[cos2x.(5)/(5x)+log(5x).(-2 sin 2x)]` `rArr" "(dy)/(dx)=3.(5x)^(3cos2x)` `" "[(cos2x)/(x)-2sin2xlog(5x)]` |
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