1.

6.02 xx 10^20molecules of urea are present in 100ml of its solution. The concentration of solution is

Answer»

0.02 M
0.01 M
0.001 M
0.1 M

SOLUTION :MOLES of urea ` = (6.02 xx 10^20)/(6.02 xx 10^23) = 10^(-3)` moles
Molarity ` = (10^(-3) )/(100) xx 1000 = 0.01 M`


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