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(6.023xx10^(23)xx1)/10^(20)=6023 sec=1.673 hrs. A 100% pure sample of a divalent metal carbonate weighing 2g on complete thermal decomposition releases 448 cc of carbon dioxide at STP. The equivalent mass of the metal is

Answer»

40
20
28
12

Solution :Divalent metal carbonate means `MCO_(3)`.
`{:(ACO_(3) overset(Delta )(rarr)MO+CO_(2)),("1 mol22400 CC"),("2 g448 cc"),("448 cc evolves from 2g"):}`
22400 cc will evolve from `2/448xx22400g=100g` i.e.,
100 G is the MOLECULAR weight of the carbonate.
Then M.W. of metal `=100-(12+3xx16)`
(wt. of carbonate, `CO_(3)^(2-)`)
`=40 g`
Equivalent weight `=("Molecular weight")/("Valency")`
`=40/2=20`.


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