6.02×10*20 molecules of urea are present in 100ml solution.the concen – InterviewSolution

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1.

6.02×10*20 molecules of urea are present in 100ml solution.the concentration of urea solution is

Answer»

Moles of urea = molecules/avogadro no

= 6.02X10^20 / 6.022 X 10^23

= 10^-3 moles

So it will have 10^-2 mole in 1 litre of solution

because

Molarity/concentration = mole / litre

= 10^-3/1L

= 10^-2M

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