1.

6.02xx10^(20) molecules of urea are present in 100 mL of its solution. The concentration of the solution is

Answer»

0.02 M
0.01 M
0.001 M
0.1 M

Solution :No. of moles of urea present in 100 mL of solution
`=(6.02xx10^(20))/(6.20xx10^(23))=10^(-3)"MOL"`
`therefore` Molar CONCENTRATION of urea in the solution
`=(10^(-3))/(100)xx1000=10^(-2)M=0.01M`


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