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`6.02xx10^(20)` molecules of urea are present in `100 mL` solution. The concentration of urea solution is:A. `0.1 M`B. `0.01M`C. `0.02 M`D. `0.001 M` |
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Answer» Correct Answer - B `M=("Moles of urea")/(V"in litre")=(6.02xx10^(20)xx1000)/(6.023xx10^(23)xx100)` `10^(-2)M` |
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