{6-1+(3/2)-1}-1(a) (2/3) (b) (5/6) (c) (6/5) (d) None of these

1.	{6-1+(3/2)-1}-1(a) (2/3) (b) (5/6) (c) (6/5) (d) None of these
Answer» (c) (6/5) We know that, = (6)^-1= (1/6) … [∵ (a/b)^-n = (b/a)ⁿ] = (3/2)^-1 = (2/3) … [∵ (a/b)^-n = (b/a)ⁿ] Now add, = {(1/6) + (2/3)}^-1 = {(1+4)/ 6}^-1 … [LCM of 6 and 3 is 6] = {5/6}^-1 = {6/5}

Answer»

(c) (6/5)

We know that,

= (6)^-1= (1/6) … [∵ (a/b)^-n = (b/a)ⁿ]

= (3/2)^-1 = (2/3) … [∵ (a/b)^-n = (b/a)ⁿ]

Now add,

= {(1/6) + (2/3)}^-1

= {(1+4)/ 6}^-1 … [LCM of 6 and 3 is 6]

= {5/6}^-1

= {6/5}

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