(6-1– 8-1)-1 = ?(a) (-1/2) (b) -2 (c) (1/24) (d) 24

1.	(6-1– 8-1)-1 = ?(a) (-1/2) (b) -2 (c) (1/24) (d) 24
Answer» (D) 24 We know that, = (6)^-1= (1/6)¹… [∵ (a/b)^-n = (b/a)ⁿ] = (8)^-1 = (1/8)¹ … [∵ (a/b)^-n = (b/a)ⁿ] Now subtract, = {(1/6) – (1/8)}^-1 = {(4-3)/24}^-1 … [LCM of 6 and 8 is 24] = {1/24}^-1 = {24/1} = 24

Answer»

(D) 24

We know that,

= (6)^-1= (1/6)¹… [∵ (a/b)^-n = (b/a)ⁿ]

= (8)^-1 = (1/8)¹ … [∵ (a/b)^-n = (b/a)ⁿ]

= {(4-3)/24}^-1 … [LCM of 6 and 8 is 24]

= {1/24}^-1

= {24/1}

= 24

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