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6.A straight wire carrying a current of 12 A is bent into a semi-circular arc of radius 2.0 cm as shown in Fig. (a). Consider the magnetic field B at the centre of the arc. a . What is the magnetic field due to the straight segments? b. In what way the contribution to B from the semicircle differs from that of a circular loop and in what way does it resemble? c. Would your answer be different if the wire were bent into a semi-circular arc of the same radius but in the opposite way as shown in Fig. (b)? |
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Answer» Solution :a. dl and r for each element of the straight segments are parallel. Therefore, d/ X = 0.Straight segments do not contribute to |B|. b. For all segments of the semicircular arc, drare all parallel to each other into the plan of the paper). All such CONTRIBUTIONS add up in magnitude. Hence direction of B for a semicircular are is given by the right-hand rule and magnitude is HALF that of a circular loop. Thus Bis `1.9 XX 10^(-4)`T normal to the PLANE of the paper going into it. c. Same magnitude of B but opposite in direction to that in (b). |
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