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6 boys and 6 girls sit in a row at random. Find the probability that all the girls sit together. |
Answer» Given there are 6 boys and 6 girls \(\therefore\) No of ways in which 6 boys and 6 girls sitting together in a row=7! 6 girls sitting arrangement = 6! \(\therefore\) required probability = \(\cfrac{7!\times6!}{12!}\) = \(\cfrac1{132}\) |
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