1.

6 boys and 6 girls sit in a row at random. Find the probability that all the girls sit together.

Answer»

Given there are 6 boys and 6 girls

\(\therefore\) No of ways in which 6 boys and 6 girls sitting together in a row=7!

6 girls sitting arrangement = 6!

\(\therefore\) required probability = \(\cfrac{7!\times6!}{12!}\)

\(\cfrac1{132}\)



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