1.

6 grams of a substance 'A' dissolved in 100 g of water freezes at - 0.93^(@)C. Themolecular mass of 'A' is (K_(f)=1.86 Km^(-1)).

Answer»

60
120
180
140

Solution :`DELTA T_(F)=0-(-0.93)=0.93`
`M_(B)=(K_(f)xx1000xx w_(B))/(w_(A)XX Delta T_(f))`
`=(1.86xx1000xx6)/(100 xx 0.93)=120`


Discussion

No Comment Found

Related InterviewSolutions