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6. The base of an isosceles triangle is 40 cm and its area is 420 cm. Find the length of its equalsides.​

Answer»

Let ABC be the ISOSCELES triangle.Area of triangle = 1/2 BASE x height ⇒height = 2 x area / base ⇒height = 21 CM→Let BC be the base and AB and AC be the equal sides of the triangle .→Let D be the POINT where height meets the base BC .→D will be the mid-point of ABC because its isosceles triangle. ⇒Given AB = AC = √(21)² + (20)² [∵ hypotenuse of triangle ADB and ADC ]⇒                          = √441 + 400⇒                          = √841 ⇒                          = 29 cm                          ∴The length of its equal  sides of triangle ABC = 29 cm


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