Saved Bookmarks
| 1. |
6.The potential energy of a particle executing SHM changes from maximum to minimum in 5 s. Then thetime period of SHM is(A) 5 s(B) 10 s(C) 15 sD) 20s |
|
Answer» potential energy oscilllates twice in the time period means the frequency of P.E = times of that of the actual oscillation so, time period with will be twice of that of P.E = 5*2 = 10s |
|