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6.The potential energy of a particle executing SHM changes from maximum to minimum in 5 s. Then thetime period of SHM is(A) 5 s(B) 10 s(C) 15 sD) 20s

Answer»

potential energy oscilllates twice in the time period

means the frequency of P.E = times of that of the actual oscillation

so, time period with will be twice of that of P.E = 5*2 = 10s



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