1.

6. To what temperature must a gas at 300 K becooled down in order to reduce its volame to3rd of its original vełume, pressure remaining(Ans. 100 K)constant?

Answer» <p>Gas equation-P¹*V¹/T¹= P²*V²/T²V¹/T¹= V²/T² (as P is constant)V¹/300= V¹/3*T²T²=100Kso, gas should be cool down to 100K.</p>


Discussion

No Comment Found