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60. The energy of the electron, in the groundstate of hydrogen, is -13.6 eV. Calculatethe energy of the photon that would beemitted, if the electron were to make atransition corresponding to the emissionof the first line of the(G) Lyman series(ii) Balmer series of the hydrogenspectrum. All India 2009C |
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Answer» Energy of an electron in hydrogen atom in ground state is -13.6 eV. En= -Z² 13.6 / n² electron volt----------1 Energy levels higher than ground energy state in an atom iscalled as excited energy state/ level. Energy of electron in second excited state means : Z=1, n=3On substituting these values in equation 1 we get . En=- (1)²x 13.6/3² electron voltEn=- 1x 13.6/9En=-1.5 electron volt. ∴Energy of the electron in the second excited state in hydrogen atom is -1.5 electron volt. |
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