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600 mL of aqueoussolutioncontining2.5g of a protein shows an osmotic pressureof 25mm Hg at 27^(@)C.Determinethe molecular mass of protein.

Answer»


Solution :`pi = cRT =(w_(2))/(M_(2)V) RT or M_(2) = (w_(2)RT)/(piV)`
`w_(2) = 2.5 g , R = 0.0821 L atm mol^(-1) K^(-1)`
` T= 273 + 27 = 300 K`
` pi = (25)/(760) atm ,V = (600)/(1000) L`
`M_(2)= ((2.5 g xx 0.0821 L atm mol^(-1)K^(-1)) xx (300K))/(((25)/(760) atm) xx((600)/(1000)L))`
` = 3119.8 g mol^(-1)`


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