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60g of urea is dissolved in 1100g solution. To keep `DeltaT//K_(f)" as "1" mol"//kg`, water separated in the form of ice isA. 40 gB. 60 gC. 100 gD. 200 g |
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Answer» Correct Answer - A 1100g" solution has 60 g urea. Thus", `"water=1040g` `DeltaT_(f)=(1000K_(f)w_(1))/(m_(1)w_(2))rArr(DeltaT_(f))/(K_(f))=(1000xx60)/(60xxw_(2))=1` `:.w_(2)=1000g` `"Thus, ice formed"=1040-1000=40g` |
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