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`60muF` capacitor to a 110 V, 60 Hz ac supply. Determine the rms value of the current in the circuit. What is the net power absorbed by the circuit over a complete cycle? |
Answer» `I_(rms)=V_(rms)/X_C` where, `X_C=1/(2pifC)=1/(2pitimes60times60times10^-6)Omega` and `V_(rms)=110V` `thereforeI_(rms)=110(2pitimes60times60times10^-6)A=2.49A` The net power absorbed is zero as in case of a ideal capacitor there is no power loss. |
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