1.

""^(64)Cu (t_(½)=12.8h) decays by beta^(-) -emission (38%), beta^(+)-emission (19%) and electron capture (43%). Write decay products and calculate partial half-lives for each of the decay processes.

Answer»

SOLUTION :`lamda_(CU)= (0.6932)/(12.8)= 0.054`

`therefore lamda_(1)` = FRACTIONAL yield of `Zn xx lamda_(Cu)= (38)/(100) xx 0.054 = 0.0205`
`therefore t_(½)` for `beta^(-)` emission `=(0.6932)/(0.0205)= 33.8h`
Similarly we can CALCULATE, `t_(½)`for `beta^(+)` emission = 67.6hand `t_(½)` for ELECTRON capture= 29.85h


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