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InterviewSolution
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64.The hybrid state of B in BF 4 is(a) sp(b) sp(c) sps(d) no specific |
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Answer» option There's a formula for hybridization: S = (1/2)*|G + M - C + A|, || means absolute value, G=number of valence electrons, M=number of monovalent atoms attached to central atom, C = cationic charge of ion(if any), A = anionic charge. S = 4, sp3 hybridizedS = 3, sp2 hybridizedS = 2, sp hybridizedS = 5, sp3d hybridizedand so on.... BF4- : G = 3, M = 4, A = 1, C = 0.'. S = (1/2)*|3+4+1| = 4i.e. sp3 hybridized! |
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